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Pierre claims not to read my posts so someone might want to draw his attention to this sketch which shows a door along the side of number 27.
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Originally posted by Elamarna View PostRobert
You surprise me.
There is no access from 26 to 27 marked on map. There are brick walls. No openings.
The map shows no entrance at the front for 26 . But there is a door there. The sketch Pierre likes to use looking at 26 shows a door.
WHAT SKETCH?
It's not on the map.
Neither are there doors for 27 28 and 29.
We can occluded the map rarely shows doors .
Steve
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Originally posted by Pierre View PostSteve,
come on. Why can´t you understand what I am saying?
My point is that there isn´t any opening on the left side in the passage, that is, on the side of McCarthy´s shop.
So HOW could the tenants living above his shop get to their rooms?
They could, if they used the opening on the right side.
There must have been a corridor above the passage. It is the only possibility.
But if there was a door going into room 13 - as we know there was - then there could also have been a door going into the room at the back of number 27 which led to a staircase. Or there could have been a staircase inside a door at the front of number 27.
So Pierre's possibility is not "the only" possibility.
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Originally posted by Robert St Devil View PostI agree with this line of thinking. I am working towards the belief that 26 and 27 were once a single unit. No. 26 was the salon and parlour, 27 was the kitchen. I have been wondering if it was a nice house when it was originally constructed, but became slummish as the East End became overrun with immigrants. Afterall, 'the court' was first considered 'the garden'. I could see the upstair rooms being accessed thru that arch passage.
You mean before 1890 then?
Because in 1890 hey weren´t a "single unit" in that meaning, since both number 27 and number 26 are shops = S. Look at the map.
But people had to be able to get up to their rooms without passing the shop. So where was the entrance to the rooms in number 27? It can ONLY have been through the side in the passage, leading first into 26, upstaris to the landing, and then left into the corridor, wich must have been a stairwell. There is a window in it. And from there you must have been able to reach the rooms both in number 26 and 27.
Regards Pierre
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Originally posted by Elamarna View PostPierre,
just take a moment and look at the goad map.
There are solid walls on the 26 side of the archway, are you now suggesting there is a unseen opening to allow people to enter 27 via the archway from 26?
come on. Why can´t you understand what I am saying?
My point is that there isn´t any opening on the left side in the passage, that is, on the side of McCarthy´s shop.
So HOW could the tenants living above his shop get to their rooms?
They could, if they used the opening on the right side.
There must have been a corridor above the passage. It is the only possibility.
Regards Pierre
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Originally posted by David Orsam View PostYes, we seem to be close but I don't know anything about a fireplace. Where are you saying that would have been?
It would have been in the brick wall, probably backing onto a fireplace in 26 sharing a chimney.
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Originally posted by GUT View PostThanks David I think we're on the same page re the construction of the wall part brick (with the fireplace) part open, thus needing a partition (or false wall).
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Originally posted by David Orsam View PostOh right, well that's the whole point. According to the Goad map, the space from Miller's Court to the "brick wall" line - originally assumed to be Mary's room - is (by my measurements) 9 feet.
However, if the end of Mary's room was a brick wall there would have been no need for any kind of wooden partition to have been erected.
That being so - and bearing in mind the evidence that there was a wooden partition - one possible explanation (or so I believed) was that a staircase was erected inside the "brick wall" thus requiring a partition to cut off Mary's room from the staircase.
Given that at least 3 feet would have been needed for the staircase, I wondered if Mary's room could in fact have been only 6 feet wide once the partition was erected.
However, on consideration, I've abandoned the idea. I now think that the "brick wall" was not a solid brick wall but contained a large opening (hence the partition was required to fill it).
As a result, there is no need for us to ponder on the size of Mary's room because it is shown on the Goad map, assuming, of course, that the map is to scale.
Thanks David I think we're on the same page re the construction of the wall part brick (with the fireplace) part open, thus needing a partition (or false wall).
Re the Scale, I've been trying to measure some of the parts that have distances marked, and I'm still to reach a conclusion.
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Originally posted by GUT View PostNot sure why you want to squeeze the staircase into Mart's room?
However, if the end of Mary's room was a brick wall there would have been no need for any kind of wooden partition to have been erected.
That being so - and bearing in mind the evidence that there was a wooden partition - one possible explanation (or so I believed) was that a staircase was erected inside the "brick wall" thus requiring a partition to cut off Mary's room from the staircase.
Given that at least 3 feet would have been needed for the staircase, I wondered if Mary's room could in fact have been only 6 feet wide once the partition was erected.
However, on consideration, I've abandoned the idea. I now think that the "brick wall" was not a solid brick wall but contained a large opening (hence the partition was required to fill it).
As a result, there is no need for us to ponder on the size of Mary's room because it is shown on the Goad map, assuming, of course, that the map is to scale.
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Originally posted by David Orsam View PostHere's my thinking GUT.
I assume Mary's bed was a double bed because Joe Barnett stayed there. If so, then having measured my own double bed it would have taken up 4 ft 3 inches in width.
The table next to the bed can't have been less than 1ft 4inches.
So we've already reached 5 ft 7 inches.
The door can't have been narrower than about 2 ft 2 inches.
Of course, when opened, the door knocked into table so we perhaps only need to add 1 ft for the door.
We now have 6 ft 7 inches taken up.
I think we have to add at least 2 more feet between the frame of the door and the edge of the room with the windows.
So that takes me to 8 ft 7 inches of space required.
Of course, if Mary's bed was a single that might give us more room to play with but I simply can't see how both Mary's room and Prater's staircase could have been squeezed into an area of only 9 foot in width.
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Originally posted by GUT View PostSo why is 15x7 or thereabouts so unreasonable?
I assume Mary's bed was a double bed because Joe Barnett stayed there. If so, then having measured my own double bed it would have taken up 4 ft 3 inches in width.
The table next to the bed can't have been less than 1ft 4inches.
So we've already reached 5 ft 7 inches.
The door can't have been narrower than about 2 ft 2 inches.
Of course, when opened, the door knocked into table so we perhaps only need to add 1 ft for the door.
We now have 6 ft 7 inches taken up.
I think we have to add at least 2 more feet between the frame of the door and the edge of the room with the windows.
So that takes me to 8 ft 7 inches of space required.
Of course, if Mary's bed was a single that might give us more room to play with but I simply can't see how both Mary's room and Prater's staircase could have been squeezed into an area of only 9 foot in width.
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David
of course I agree with you, would show the whole wall as partition myself.
Was just concerned Richard has had so much info given to him,might be best to leave it as in his last plan. However I do understand where you are coming from.
Stevek
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Originally posted by Elamarna View PostDavid
However the map indicates it is brick.
I don't think that this simple point can possibly confuse Richard. I also think it's more evidence based for the partition to be wider.
I might add that under normal circumstances I personally wouldn't care at all about the width of the partition but it seems to have taken on a greater significance due to Pierre's theory and, having now thought about it, that seems to me to be the most likely answer.
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