[QUOTE=David Orsam;388956]
Hi Steve,
The content of the tickets are what they are. There is a total amount of letters. They are simply there. There is nothing to do but accept it.
A random selection is not done in relation to the pawn tickets. It is done from a larger archive, where you have cases containing two names and two addresses. You test the cases (drawn randomly) by searching for the letters in those cases. If you find them you note it and go ahead with the rest.
The point is that you should have a sample that resembles the data from 1888 as much as possible, so therefore you need two names and two addresses and preferably from Whitechapel, since the possibilities of street selection should match the tickets.
Do you understand?
This is always a problem when you do history and it is a common problem generally in a lot of studies. You seldom see the original sources. If you study art, you could go and look at paintings in the Louvre but more often you use reproductions in books. You study another galax in space but you do not see it or touch it. For an historian, there are is source criticism and discussing problems, those are the tools. Nothing controversial at all.
Well, I understand that you just want to know something about letters now, but that is not the issue here. The issue is the probability.
That question is no problem either. The contents are what they are, even if you try to use them in different versions. The probability is what is important here.
Best wishes, Pierre
Out of interest, Pierre, are you going to factor into your calculations the fact that you made a conscious decision to select a certain number of words from the pawn tickets? I mean, you could have just found the name of your suspect in the two names "Jane Kelly" and "Emily Birrell" excluding the addresses. Or he could have been found in just the two addresses "White's Row" and "Dorset Street" excluding the names. But you deliberately decided to choose all four didn't you? i.e. the two names AND the two addresses. So is that a truly random selection of 42 characters I wonder?
The content of the tickets are what they are. There is a total amount of letters. They are simply there. There is nothing to do but accept it.
A random selection is not done in relation to the pawn tickets. It is done from a larger archive, where you have cases containing two names and two addresses. You test the cases (drawn randomly) by searching for the letters in those cases. If you find them you note it and go ahead with the rest.
The point is that you should have a sample that resembles the data from 1888 as much as possible, so therefore you need two names and two addresses and preferably from Whitechapel, since the possibilities of street selection should match the tickets.
Do you understand?
Also, are you going to factor into your calculations the fact that you've never seen the original pawn tickets or any form of reproduction on them? There strikes me as being two consequences of that.
Firstly, some newspapers said the Dorset Street pawn ticket was in the name of "Anne Kelly" not "Jane Kelly". In the absence of any official sources, how do we know which one (if either) is correct? If the former was the right name, does the absence of the "J" affect the outcome?
Secondly, how do we know if the pawn ticket said "Dorset Street" and not "Dorset St"? If the latter, which strikes me as more likely for a pawnbroker to have written on the ticket, that will reduce the number of characters to 38 so that, if you only have 2 or 3 characters left over, the name of your suspect will not be included. And if that's the case then the whole thing is redundant isn't it?
Best wishes, Pierre
Comment